Get the block that is "x" away from the player (in his direction)

Code:

 public static double lengthdir_x(double len, double dir) {
return len * Math.cos(Math.toRadians(dir));
}
 
public static double lengthdir_y(double len, double dir) {
return -len * Math.sin(Math.toRadians(dir));
}
 
public Block getBlockXAway(Player p, double distance) {
Location ploc = p.getLocation().add(0,2,0);
double pitch = -ploc.getPitch();
double direction = -ploc.getYaw()-90;
System.out.println(pitch);
System.out.println(direction);
int xx = (int) (ploc.getBlockX() + ( lengthdir_x(distance, direction) * lengthdir_x(1, pitch)));
int yy = (int) (ploc.getBlockY() + (-lengthdir_y(distance, pitch)));
int zz = (int) (ploc.getBlockZ() + ( lengthdir_y(distance, direction) * lengthdir_x(1, pitch)));
Location nloc = new Location(ploc.getWorld(), xx, yy, zz);
Block b = nloc.getBlock();
return b;
}

What I wrote above works perfectly. It finds the player, his direction, and gets the block that is "x" away from the player and still is in his line of sight. However, I want to know whether or not this is the fastest way to go about this. Is it?

 

You're not using any loops, so the difference between your method and any other method will be pretty negligible.