Getting Integers from Lores

I have been trying to get the int for both "Success Rate" and "Destroy Rate"
I will give the example of what I have so far it it is currently picking up the Success Rate as
"Rate 91%" amd thats causing a NumberFormatException.
Please comment if you have any idea on how to fix this, thanks.
​

Code:

    public static int getDestroyRate(ItemStack i) {
        if(i != null && i.hasItemMeta() && i.getItemMeta().hasLore()) {
            List<String> lore = i.getItemMeta().getLore();
            for(String s : lore) {
                s = ChatColor.stripColor(s);
                if(s.contains("Destroy Rate")) {
                    int value = Integer.parseInt(s.substring(s.indexOf(" ") + 1));
                    return value;
                }
            }
        }

        return 0;
    }
    public static int getSuccessRate(ItemStack i) {
        if(i != null && i.hasItemMeta() && i.getItemMeta().hasLore()) {
            List<String> lore = i.getItemMeta().getLore();
            for(String s : lore) {
                s = ChatColor.stripColor(s);
                if(s.contains("Success Rate")) {
                    int value = Integer.parseInt(s.substring(s.indexOf(" ") + 1));
                    return value;
                }
            }
        }

        return 0;
    }

 

Most likely due to the percentage sign at the end, have you tried getting a substring and excluding the % sign at the end?
Example:
int value = Integer.parseInt(s.substring(s.indexOf(" ") + 1, s.indexOf("%")));

Edit: Ninja'd @mcdorli

Or
int value = Integer.parseInt(s.replaceAll("[^0-9]"));

 

Get the string
Remove Success Rate and %
Integer.parseInt(<what you got>)

 

After getting the string how do I remove Success Rate and %?

 

String#replace("Success Rate", "");
String#replace("%", "");

 

EDIT: both mcdorli's method and mine will work, but mine will work on any text in your lore, as long as the last word contains your number

String#split(" ")[2].replace("%", "")

 

There is no method like String#split(Int i), only String#split(char[]), and split returns an array of strings
you could do String#split(" ")[2].replace("%", "")

 

That's what i meant -.- I'm on a phone lol

I'll edit it into mine, once this damn website lets me click anything

 

I feel your pain. I'm often from a phone too.

 

@mcdorli

Code:

public static int getSuccessRate(ItemStack i) {
        if(i != null && i.hasItemMeta() && i.getItemMeta().hasLore()) {
            List<String> lore = i.getItemMeta().getLore();
            for(String s : lore) {
                s = ChatColor.stripColor(s);
                if(s.contains("Success Rate")) {
                    s.replace("Success Rate", "");
                    s.replace("%", "");
                    int value = Integer.parseInt(s);
                    return value;
                }
            }
        }

        return 0;
    }

}

This is returning "Success Rate 91%" and still catching the "NumberFormatException"

@mcdorli

Code:

public static int getSuccessRate(ItemStack i) {
        if(i != null && i.hasItemMeta() && i.getItemMeta().hasLore()) {
            List<String> lore = i.getItemMeta().getLore();
            for(String s : lore) {
                s = ChatColor.stripColor(s);
                if(s.contains("Success Rate")) {
                    s.replace("Success Rate", "");
                    s.replace("%", "");
                    int value = Integer.parseInt(s);
                    return value;
                }
            }
        }

        return 0;
    }

}

This is returning "Success Rate 91%" and still catching the "NumberFormatException"

EDIT by Moderator: merged posts, please use the edit button instead of double posting.

 

@xxPatterson You have to set s to the new value. e.g. s = s.replace(...)

 

you must do it like this:

s = s.replace(...);

also instead of "Success Rate" use "Success Rate " because there is also a space character after success rate which will cause exception while parseInt, if not removed.