Solved Percentage Chances

this is a question off the top of my head so I have no code to show, but how would I make an event that has chances of something happening for example onPlayerJoinEvent there has a chance for them to get a diamond how would I do this ?

EDIT: with permissions could be more helpful for example playerjoin.chance.25 > 25% chance to get a diamond on join

 

Well for a 25% chance, 100/25 = 4. Therefor you could use https://stackoverflow.com/questions/5887709/getting-random-numbers-in-java#5887736 or the random class to do:

Code:

Random rand = new Random();
int value = rand.nextInt(4);
if(value == 0){
//Do stuff
}

Doing rand.nextInt(4); gives you a random number between 0-3 meaning you would have a 25% chance of getting 0. However, you have to remember that it is never random, and there is always a pattern of the numbers rand returns, so I would do some research on it.

 

@MelonCola So something like this could do the job?

Code:java

import java.util.Random;
 
Random rand = new Random();
 
int n = rand.nextInt(4) + 1;

 

Yes, doing that would result in n equaling a not so random random number between 1-4.

 

You shouldn't do that, it's harder to use and read.

Just make a method like this:

Code:

public static Boolean percentChance(double chance) {
    return Math.random() <= chance;
}

Then in your case, you could do something like this for 25%:

Code:

if (percentChance(0.25)) {
    // do something
}