Is this the fastest way to get the block x away from where the player is looking?

Code:

    public static double lengthdir_x(double len, double dir) {
        return len * Math.cos(Math.toRadians(dir));
    }
 
    public static double lengthdir_y(double len, double dir) {
        return -len * Math.sin(Math.toRadians(dir));
    }
 
    public Block getBlockXAway(Player p, double distance) {
        Location ploc = p.getLocation().add(0,2,0);
        double pitch = -ploc.getPitch();
        double direction = -ploc.getYaw()-90;
        System.out.println(pitch);
        System.out.println(direction);
        int xx = (int) (ploc.getBlockX() + ( lengthdir_x(distance, direction) * lengthdir_x(1, pitch)));
        int yy = (int) (ploc.getBlockY() + (-lengthdir_y(distance, pitch)));
        int zz = (int) (ploc.getBlockZ() + ( lengthdir_y(distance, direction) * lengthdir_x(1, pitch)));
        Location nloc = new Location(ploc.getWorld(), xx, yy, zz);
        Block b = nloc.getBlock();
        return b;
    }

Would this be the fastest way to get a block that is "x" away from the player (in the direction he is looking)?

[EDIT]
wrong forum, my bad.