If args[0] is an INTEGER

I am using the following code in my time command:

http://pastebin.com/PrJ73T2P

How can I check if args[0] is an int so players can also do /time 0 .

Help would be greatly appreciated
Keir

 

I use these methods:

Code:java

public static int getInt(String string) {
if (isInt(string)) {
return Integer.parseInt(string);
}
else {
return 0;
}
}
 
public static boolean isInt(String string) {
try {
Integer.parseInt(string);
} catch (NumberFormatException nFE) {
return false;
}
return true;
}

 

I'll try that out, thanks!

 

This function has 4 issues:
1. If the input isn't an integer, a NumberFormatException is thrown.
2. Integer.equals(string) does either not work or is a waste of CPU cycles.
these two are minor, but still:
3. If you don't need an instance of Integer don't use one. Use an int wherever possible.
4. "if (boolean) return true; else return false;" is equal to "return boolean;".

 

This looks like the perfect one, thanks.

 

Except that it parses the number 2 times where once would be enough:

Code:java

public static int getInt(String string) {
try {
return Integer.parseInt(string);
} catch (NumberFormatException nFE) {
return 0;
}
 
}
 
public static boolean isInt(String string) {
try {
Integer.parseInt(string);
} catch (NumberFormatException nFE) {
return false;
}
return true;
}

 

I haven't tried this, but you might be able to use this.

Code:java

if (args[0].matches("[-+]?\\d+(\\.\\d+)?") == true) {
    //Do stuff
    return true;
} else {
    //Send them a message or something
}

Source: at about 3:35

 

Here's how I would do it:

try{
Integer.parseInt(args[0]);
//Do stuff here. Will only execute if the above code doesn't throw an exception.
} catch(Exception e) {
//Do other stuff. In this case, it's not an int.
}

 

Thanks for all your replies! When I get back to my coding pc I will try these out. Thanks