Solved getting location of a block when left clicked

So i've googled for a while and i can't find how to get the location of the block when i left click i use the onPlayerUse(PlayerInteractEvent event) thing so here is what i got atm

Code:java

 @EventHandler(priority = EventPriority.HIGHEST)
public void onPlayerUse(PlayerInteractEvent event) {
if(event.getAction() == Action.LEFT_CLICK_BLOCK) {
// Anything
}
}

And i hope you can help me.

 

Try using the event.getInteractedBlock() method...?

Code:java

@EventHandler(priority = EventPriority.HIGHEST)
public void onPlayerUse(PlayerInteractEvent event) {
if(event.getAction() == Action.LEFT_CLICK_BLOCK) {
Block b = event.getInteractedBlock();
Location loc = b.getLocation(); //make sure you're importing the right Location, the one from org.bukkit.
//if you need the double forms of the x, y, z, pitch, or yaw, use loc.getX(), loc.getY(), loc.getZ(), etc.
}
 
}

If you're ever confused about something, try looking it up in the javadocs before posting a thread here. This link will take you straight to the PlayerInteractEvent class.

 

Thanks alot, helped alot!

The getInteractedBlock doesn't exist I suppose i you mean't getClickedBlock() method.

EDIT by Moderator: merged posts, please use the edit button instead of double posting.

 

please mark thread as solved, when its solved

 

ninja2003 Depends on what version of bukkit you're running. In the links I provided, 1.7.10-R0.1 was used. That version uses getInteractedBlock() while older versions use getClickedBlock().

 

Oh didn't even know the 1.7.10 was out Can't wait for the full version of minecraft 1.8 and bukkit