Checking an Argument

How can I check if the third argument of a command is a integer? (/Test Test Int) And how would I get that Integer? Thanks

 

Use args


if (args.length == 0) {
//do something
}else if(args.length == 1{
if (args[0].equalsIgnoreCase("test")) {
//do some
}
}
}

 

https://docs.oracle.com/javase/7/docs/api/java/lang/Integer.html#parseInt(java.lang.String)

 

diamondcodes
Arrays and the length act differently. Arrays ([]) use the 0-(size of array), but the length actually shows how many of them there are (Example: /<0> <1> <2> <3> (Size is 3, but to get the 3rd arg, use args[2])).
Also, to get an int, use Integer.parseInt(String) as teej107 said.

 

To turn a string to int, use Integer.parseInt(string) its a good idea to handle a possible exception, that occurs when the string is not number but contains other characters as well.

 

Actually the command name is not counted as an argument, it would be : /cmd <o> <1> <2>. Therefore the integer diamondcodes is looking for is the 2nd argument, or args[1].

 

Code:java

try{
    int theInt = Integer.parseInt(args[1]);
}catch(NumberFormatException e){
    return false;
}

 

Totom3
What I meant is what length he should be using for each case.