Tutorial Get the craftbukkit version (+ little regex tut)

Code:java

String version = Bukkit.getVersion();

this would return something like: git-Bukkit-1.7.2-R0.3-14-g8f8716c-b3042jnks (MC: 1.7.5)

But we want to get rid of the rest and just keep the version (in this case 1.7.5). Use regexes and the replace method:

Code:java

.replaceAll(".+ \\(MC: ", "").replace(")", "")

Final code:

Code:java

String version = Bukkit.getVersion().replaceAll(".+ \\(MC: ", "").replace(")", "");

Thats how the regex works:
.+ the . is for every character and the + extends the 'every char' until a whitespace.
Next is a whitespace.
Next we use the escaped char for ( -> \\( because (http://www.regular-expressions.info/named.html)
Next just the characters 'MC: '
And finally use the .replace method to remove the last )
For a more detailed regex tutorial visit this site: http://regexone.com

 

Locked.

Java is a requirement for Bukkit.
And because of that basic Java Tutorials are unnecessary here.
And the modification of Strings is basic Java.